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x^2-10.2x+2=0
a = 1; b = -10.2; c = +2;
Δ = b2-4ac
Δ = -10.22-4·1·2
Δ = 96.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10.2)-\sqrt{96.04}}{2*1}=\frac{10.2-\sqrt{96.04}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10.2)+\sqrt{96.04}}{2*1}=\frac{10.2+\sqrt{96.04}}{2} $
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